Limit of a series

: Math 2730 Sequences and Series: Limit of a series
   By Martin Daniels on Tuesday, April 22, 2008 - 07:22 pm: Edit Post

The question is:

Determine whether the sequence a(n) = 2^n/n^n converges and then find its limit.

I think I know how to show that it converges using the fact that (2/n)^n needs to decrease, ie n>2.

But I have no idea how to find its limit. I don't know how to treat things of the x^x nature.


   By Sasho on Tuesday, April 22, 2008 - 08:24 pm: Edit Post

It was done in class. Here it is, again:

0<2n/nn = 2.2.2.....2/n.n.....n =(2/n)(2/n)...(2/n)<2/n

Use the squeeze theorem and apply the limit to the extremities of the above inequality.


Posting is currently disabled in this topic. Contact your discussion moderator for more information.